5-3sin^2x-4cosx=4

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Solution for 5-3sin^2x-4cosx=4 equation: 


Simplifying
5 + -3sin2x + -4cosx = 4

Reorder the terms:
5 + -4cosx + -3in2sx = 4

Solving
5 + -4cosx + -3in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -4cosx + -5 + -3in2sx = 4 + -5

Reorder the terms:
5 + -5 + -4cosx + -3in2sx = 4 + -5

Combine like terms: 5 + -5 = 0
0 + -4cosx + -3in2sx = 4 + -5
-4cosx + -3in2sx = 4 + -5

Combine like terms: 4 + -5 = -1
-4cosx + -3in2sx = -1

Add '3in2sx' to each side of the equation.
-4cosx + -3in2sx + 3in2sx = -1 + 3in2sx

Combine like terms: -3in2sx + 3in2sx = 0
-4cosx + 0 = -1 + 3in2sx
-4cosx = -1 + 3in2sx

Divide each side by '-4osx'.
c = 0.25o-1s-1x-1 + -0.75in2o-1

Simplifying
c = 0.25o-1s-1x-1 + -0.75in2o-1

Reorder the terms:
c = -0.75in2o-1 + 0.25o-1s-1x-1

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